Formulation of a buffer solution - (Dec/05/2005 )
HI
I'm not familiar with this particular method of expressing the formulation of a buffer solution.
8U/mol 0.05 mol/Na-citrate/HCl.
I think I need to first make 0.05mol/L of Na-citrate in HCl.
What does 8u/mol mean? Do I need to add 8U of the chemical in volume that contains 1 mol of Na-Citrate?
Please help me figure this out.
Thanks so much.
-ruchis-
Hi,
8U/mol is refers 8 units of X( X= Unkown chemical ) is present in 1 mol solution./ If u take l mole of that solution it contains 8 units of X ok.
Then 0.05 mol Na citatrare/HCl. That is prepare 0.05 mole Na citrate and adjust pH with HCl
Here no need to prepare 1 ltr of 0.05 mol, prepare stock of 0.5 mole {10 x ( x= times ) }, then dilute to 1x (0.05 mol )
It may help U,
Bye
-shiva-
QUOTE (shiva @ Dec 13 2005, 09:28 AM)
Hi,
8U/mol is refers 8 units of X( X= Unkown chemical ) is present in 1 mol solution./ If u take l mole of that solution it contains 8 units of X ok.
Then 0.05 mol Na citatrare/HCl. That is prepare 0.05 mole Na citrate and adjust pH with HCl
Here no need to prepare 1 ltr of 0.05 mol, prepare stock of 0.5 mole {10 x ( x= times ) }, then dilute to 1x (0.05 mol )
It may help U,
Bye
i didn't agree with what above said. 8U/mol is refers 8 units of X( X= Unkown chemical ) is present in 1 mol solution./ If u take l mole of that solution it contains 8 units of X ok.
Then 0.05 mol Na citatrare/HCl. That is prepare 0.05 mole Na citrate and adjust pH with HCl
Here no need to prepare 1 ltr of 0.05 mol, prepare stock of 0.5 mole {10 x ( x= times ) }, then dilute to 1x (0.05 mol )
It may help U,
Bye
-forrest gump-