T7 and DH5 alpha - Help me clear out some things (Feb/04/2010 )
Hello!
I'm doing my masters thesis and I'm trying to clear some things out so that I understand them fully. Now I'm investigating the T7 expression system. If I understand things right, the T7 RNA polymerase is usually incorporated into the chromosomal genome under control of a lac operator starting transcription with the addition of IPTG. Then, the polymerase finds the T7 promotor on the plasmid and starts transcribe mRNA from this site.
However, I read somewhere that my bacterial strain, DH5 alpha, does not carry its own T7 RNA polymerase gene, and that this should be present on the plasmid and need to be transformed. Is this true? I'm suspecting it's not, because I can't see that my plasmids (pTZ19R and pSE420) contains any such thing. Could you help me clear things out?
What you read is correct. Most T7 expression is done in strains of bacteria that have been lysogenized with the DE3 phage, carrying the T7 RNA polymerase under control of the lac promoter. DH5a does not have this. Usually strains having this modification are indicated in their name, such as BL21 (DE3). The reason DH5a does not typically carry this modification is that it is poor for protein expression, since it still has the lon protease, which tends to degrade expressed proteins. The BL21 strain is knocked out for this and other proteases.
You could certainly carry the lac promoter and T7 RNA polymerase gene on a plasmid (either the same one or a co-transforming one) in DH5a. Few people do this, because they care about the protein expression resulting.
Thank you for your answer! I was hoping I got things wrong so they would make more sense though.. I went back to my original source, and they clone my gene into a pTZ19R expression vector and transform into DH5a for expression. If DH5a is a poor gene expression strain, why would anyone want to do that? And how does expression take place if there is no T7 RNA polymerase?
I have tried researching the subject now, but all it does is getting me more confused. I found this in some Invitrogen information document:
Important: DH5α E. coli does not require IPTG to induce expression from the lac promoter even
though the strain expresses the Lac repressor. The copy number of most plasmids exceeds
the repressor number in the cells. If you are concerned about obtaining maximal levels of
expression, add IPTG to a final concentration of 1 mM.