Case-control study using SPSS one way ANOVA - (Nov/22/2014 )

Hi,

I'm using SPSS version 20 in the statistical analysis of my study. It's a case-control study, within the cases there are three polymorphisms (TT, Tt, tt) and their correspondent vitamin D level.

when I perform one way NOVA the dependent factor (polymorphism) doesn't appear i uploaded a picture of the problem, I have labeled the different polymorphisms into 1,2,3

I want to find p-value for vitamin D level between case and control groups, also the p-value between the different polymorphisms within each side, i.e. within Case and Control

P.S.If posting the data might help in understanding my problem, I will post them

Thanks in advance

-sayk-

It's long time ago that I worked with SPSS, but if you look at your left column, the numbers are on the left side of each cell, whereas in the right column it's opposite. It seems that this is similar to Excel where non-numeric input is on the left side of each column (e.g. text).

So you might have a look on the variables view (if it's there) in SPSS to check which format this left column has and then change it to numeric (now it might be string which is then not accepted as input for ANOVA).

PS please no double posts, you can edit your first one to change or add content.

-hobglobin-

hobglobin on Sat Nov 22 11:47:58 2014 said:

It's long time ago that I worked with SPSS, but if you look at your left column, the numbers are on the left side of each cell, whereas in the right column it's opposite. It seems that this is similar to Excel where non-numeric input is on the left side of each column (e.g. text).

So you might have a look on the variables view (if it's there) in SPSS to check which format this left column has and then change it to numeric (now it might be string which is then not accepted as input for ANOVA).

PS please no double posts, you can edit your first one to change or add content.

Thanks for the reply and sorry for the double post

How can I find the p value for case control vitamin d level and p value for each polymorphism case against control ex vitamin d level for TT in the case and TT in the control

Thanks in advance

-sayk-

I'd say (if I understood it right, since I'm not a case-control study expert) that you can use a nested ANOVA (which has the same prerequisites as a normal one, such as homogeneity of variances etc). You can find enough information about it with a google search (e.g.). Hopefully SPSS can perform this too (?).

-hobglobin-